10cos^2(x)+-5sin(2x)=4

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Solution for 10cos^2(x)+-5sin(2x)=4 equation: 


Simplifying
10cos2(x) + -5sin(2x) = 4

Multiply cos2 * x
10cos2x + -5sin(2x) = 4

Remove parenthesis around (2x)
10cos2x + -5ins * 2x = 4

Reorder the terms for easier multiplication:
10cos2x + -5 * 2ins * x = 4

Multiply -5 * 2
10cos2x + -10ins * x = 4

Multiply ins * x
10cos2x + -10insx = 4

Solving
10cos2x + -10insx = 4

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '10insx' to each side of the equation.
10cos2x + -10insx + 10insx = 4 + 10insx

Combine like terms: -10insx + 10insx = 0
10cos2x + 0 = 4 + 10insx
10cos2x = 4 + 10insx

Divide each side by '10os2x'.
c = 0.4o-1s-2x-1 + ino-1s-1

Simplifying
c = 0.4o-1s-2x-1 + ino-1s-1

Reorder the terms:
c = ino-1s-1 + 0.4o-1s-2x-1

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